tea.mathoverflow.net - Discussion Feed (Cleanup) 2018-11-04T12:58:49-08:00 http://mathoverflow.tqft.net/ Lussumo Vanilla & Feed Publisher Scott Morrison comments on "Cleanup" (22035) http://mathoverflow.tqft.net/discussion/1589/cleanup/?Focus=22035#Comment_22035 2013-05-08T16:58:13-07:00 2018-11-04T12:58:49-08:00 Scott Morrison http://mathoverflow.tqft.net/account/3/ Thanks Andres, sorry I forgot to link! Thanks Andres, sorry I forgot to link!

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Andres Caicedo comments on "Cleanup" (22012) http://mathoverflow.tqft.net/discussion/1589/cleanup/?Focus=22012#Comment_22012 2013-05-07T18:38:03-07:00 2018-11-04T12:58:49-08:00 Andres Caicedo http://mathoverflow.tqft.net/account/251/ It would have been nice to have a link to the question they come from as well: http://mathoverflow.net/questions/129706/zeta3-in-terms-of-derivatives-of-zeta-at-1-2-and-pi Scott Morrison comments on "Cleanup" (22007) http://mathoverflow.tqft.net/discussion/1589/cleanup/?Focus=22007#Comment_22007 2013-05-07T17:42:36-07:00 2018-11-04T12:58:49-08:00 Scott Morrison http://mathoverflow.tqft.net/account/3/ I deleted some comments, which are think are no longer relevant (an erroneous comment, its correction, and retraction), because of weird typesetting issues that were causing them to spill way off the ... I deleted some comments, which are think are no longer relevant (an erroneous comment, its correction, and retraction), because of weird typesetting issues that were causing them to spill way off the page, and someone complained. For posterity, here they are:


I cannot reproduce your equality in Mathematica: your rhs is about 49, see code: N[(-Zeta'''[1/2]/Abs[Zeta[1/2]] - 3 Zeta''[1/2] Zeta'[1/2]/Abs[Zeta[1/2]]^2 - 2 Zeta'[1/2]^3 Abs[Zeta[1/2]]^3 - Pi^3/4)/7, 30] – Per Alexandersson 2 days ago

@Per I don't have Mathematica. Is it possible you are working with low precision? This Wolfram Alpha query returns error 10^(-15): wolframalpha.com/input/…z_2z_1%2Fz_12^2+-2*z_1^3%2Fz_12^3+-+pi^3+%2F+%284%29%29%2F7%29%2Cz_3%3DRiemannZeta%27%27%27[1%2F2.0]%2Cz_2%3DRiemannZeta%27%27[1%2F2.0]%2Cz_1%3DRiemannZeta%27[1%2F2.0]%2Cz_12%3DAbs%28RiemannZeta%281%2F2.0%29%29 – joro 2 days ago
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@Per: you are missing a / in the second to last term. – Jack Huizenga 2 days ago

@Jack: Thanks! – Per Alexandersson 2 days ago

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