tea.mathoverflow.net - Discussion Feed (math overflow.net question No.78294) Sun, 04 Nov 2018 13:49:33 -0800 http://mathoverflow.tqft.net/ Lussumo Vanilla 1.1.9 & Feed Publisher José Figueroa comments on "math overflow.net question No.78294" (16611) http://mathoverflow.tqft.net/discussion/1175/math-overflownet-question-no78294/?Focus=16611#Comment_16611 http://mathoverflow.tqft.net/discussion/1175/math-overflownet-question-no78294/?Focus=16611#Comment_16611 Tue, 18 Oct 2011 13:01:35 -0700 José Figueroa Dear garadeb2,

Meta is not for answers to closed questions. It is for discussions concerning the running of the main site. Do you object to the question being closed?

]]> garabed2 comments on "math overflow.net question No.78294" (16610) http://mathoverflow.tqft.net/discussion/1175/math-overflownet-question-no78294/?Focus=16610#Comment_16610 http://mathoverflow.tqft.net/discussion/1175/math-overflownet-question-no78294/?Focus=16610#Comment_16610 Tue, 18 Oct 2011 12:11:57 -0700 garabed2 and was closed for being "too localized". But since I can answer it , I could perhaps present the answer here.
The desired formula for d>R or d=R is 2*pi*(1-K) where K is the non-negative square root of (1-((R/d)^2)) and
d is the distance between the sphere's center and P. ]]>