tea.mathoverflow.net - Discussion Feed (Why has this answer been deleted?) Sun, 04 Nov 2018 12:59:49 -0800 http://mathoverflow.tqft.net/ Lussumo Vanilla 1.1.9 & Feed Publisher abatkai comments on "Why has this answer been deleted?" (21676) http://mathoverflow.tqft.net/discussion/1560/why-has-this-answer-been-deleted/?Focus=21676#Comment_21676 http://mathoverflow.tqft.net/discussion/1560/why-has-this-answer-been-deleted/?Focus=21676#Comment_21676 Mon, 25 Mar 2013 02:35:28 -0700 abatkai justcurious comments on "Why has this answer been deleted?" (21675) http://mathoverflow.tqft.net/discussion/1560/why-has-this-answer-been-deleted/?Focus=21675#Comment_21675 http://mathoverflow.tqft.net/discussion/1560/why-has-this-answer-been-deleted/?Focus=21675#Comment_21675 Mon, 25 Mar 2013 00:41:01 -0700 justcurious darijgrinberg comments on "Why has this answer been deleted?" (21673) http://mathoverflow.tqft.net/discussion/1560/why-has-this-answer-been-deleted/?Focus=21673#Comment_21673 http://mathoverflow.tqft.net/discussion/1560/why-has-this-answer-been-deleted/?Focus=21673#Comment_21673 Sun, 24 Mar 2013 19:50:59 -0700 darijgrinberg Ah, I see! Voting to undelete then, and if possible to scan through the other deleted posts from the same author.

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François G. Dorais comments on "Why has this answer been deleted?" (21672) http://mathoverflow.tqft.net/discussion/1560/why-has-this-answer-been-deleted/?Focus=21672#Comment_21672 http://mathoverflow.tqft.net/discussion/1560/why-has-this-answer-been-deleted/?Focus=21672#Comment_21672 Sun, 24 Mar 2013 17:53:27 -0700 François G. Dorais There is an old story here and I think this answer was deleted as part of it. You might be able to figure things out if you check meta threads around the end of April 2010. I don't think anybody would mind if it got undeleted.

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Asaf Karagila comments on "Why has this answer been deleted?" (21671) http://mathoverflow.tqft.net/discussion/1560/why-has-this-answer-been-deleted/?Focus=21671#Comment_21671 http://mathoverflow.tqft.net/discussion/1560/why-has-this-answer-been-deleted/?Focus=21671#Comment_21671 Sun, 24 Mar 2013 16:17:21 -0700 Asaf Karagila You cannot delete your own posts in the following cases:

  1. You are an unregistered user.
  2. You are trying to delete an accepted answer.
  3. You are trying to delete a question with an upvoted answer.

This is my experience from SE 2.0, but I believe that this feature is shared with MO and its obsolete software.

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quid comments on "Why has this answer been deleted?" (21670) http://mathoverflow.tqft.net/discussion/1560/why-has-this-answer-been-deleted/?Focus=21670#Comment_21670 http://mathoverflow.tqft.net/discussion/1560/why-has-this-answer-been-deleted/?Focus=21670#Comment_21670 Sun, 24 Mar 2013 15:52:08 -0700 quid Only regarding the final comment: Since there is a badge [disciplined] for deleting a post with at least +3 the fact that it was possible to delete it does not seem so suprising to me. (AFAIK only accepted answers, and questions with good [in the sense of score] answers are problematic to delete.)

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darijgrinberg comments on "Why has this answer been deleted?" (21669) http://mathoverflow.tqft.net/discussion/1560/why-has-this-answer-been-deleted/?Focus=21669#Comment_21669 http://mathoverflow.tqft.net/discussion/1560/why-has-this-answer-been-deleted/?Focus=21669#Comment_21669 Sun, 24 Mar 2013 15:28:01 -0700 darijgrinberg http://mathoverflow.net/revisions/14708/list

Answer by user "VA" to question http://mathoverflow.net/questions/14613 :

"This is just to add 1% to Dmitri's 99% complete answer. Change the coordinates to $w_0,\dots, w_{n-1}$ defined by the formula

$$ w_i = x_0 + \mu^i x_1 + \mu^{2i} x_2 + \dots, $$

where $\mu$ is a primitive $n$-th root of identity. Then the ring of invariants is the subring of monomials

$$ w_0^{k_0}\dots w_{n-1}^{k_{n-1}} \quad \text{such that}\quad n\ |\ k_1 + 2k_2 + \dots (n-1) k_n$$

and a set of generators can be obtained by taking minimal such monomials (i.e. not divisible by smaller such monomials). And relations between these generators are of the form (monomial in $w_i$) = (another monomial in $w_i$). That's a pretty easy presentation by any standard.

P.S. This works over $\mathbb C$ or any ring containing $1/n$ and $\mu$."

Notice that this answer, while not adding any new ideas, noticeably improves upon the exposition of Dmitri's one. It is voted +3, so I am surprised the author was able to delete it in the first place...

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