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Is this question acceptable?: How are the non-real roots of a quadratic function represented in RxR

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    • CommentAuthorAJ
    • CommentTimeOct 1st 2011 edited
     
    When I have, let's say, f(x) = x^2 + 4
    Their roots are x=-2i and x=2i. Do they have any meaning in the Cartesian plane? I they do, what is the explanation?

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    What do you think? Is it acceptable?



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    I'm going to post in meta.mo everytime I need to ask something on MO
    • CommentAuthorquid
    • CommentTimeOct 1st 2011 edited
     

    AJ I am afraid this question is not acceptable for MO. In general and roughly speaking the background in mathematics that is assumed on MO is about five years of university-education in mathematics. However, there is a very similar site http://math.stackexchange.com/ that welcomes mathematical question on all levels. On that other site I think your question is suitable.

    Since you are already here a short remark: you can read about geometric interpretations of complex numbers for example on the wikipidea page Compex Plane ; also called Argand Plane.

  3.  

    Not acceptable, by a long shot. In fact, based on this question alone, I urge that you not post any more questions at MO or at meta until you have learned a whole lot more. You should use math.stackexchange.com in the meantime.

  4.  

    Quid and Todd are exactly right. Math.SE is a much better site for you to use. With your level of background there is basically no question you could ask which would not get closed here. However, this is nothing to be ashamed of, Math.SE is a great site and there's nothing wrong with being a beginner in a subject.

    • CommentAuthorAJ
    • CommentTimeOct 1st 2011
     
    @Quid: about your second paragraph: what I wanted to know is if it's posible to represent both the parabola (in the classic RxR plane) and their 'imaginary' roots. Not only roots in Complex plane

    Well, I'll start to post questions at Math.SE. Two frustrated questions in a row.
    I'd like to have met Math.SE from the start


    Thank you for your advices.
    • CommentAuthorAJ
    • CommentTimeOct 1st 2011
     
    Yes, I've already found there what I needed to know :)

    Thanks for your time!

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