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Community: Why my question was closed?

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    • CommentAuthorAnixx
    • CommentTimeJan 12th 2011
     
    People, I wonder why my question about possible cklasses of linear operators was closd: http://mathoverflow.net/questions/51829/are-there-linear-operators-which-do-not-belong-to-the-following-classes

    I really fail to see how this general question about operator classes may be "too localized".
  2.  

    Anixx- The reasons for closing were not chosen by us, so for many questions there's no very good choice. If you prefer, I can go back and switch the reason to "not a real question" or "off-topic."

    • CommentAuthorBen Webster
    • CommentTimeJan 12th 2011 edited
     

    As for why it was closed, you left out so many details that it was completely unanswerable. You hadn't specified a space of functions to use when the question was closed and if you really mean "any function of complex variable" then you have to specify which axioms of set theory you want to use (I have no idea what " I would like to see a counterexample which is impossible with axiom of choice" is supposed to mean. That you don't want counterexamples which require the axiom of choice?). Not to mention that if you want to allow non-differentiable functions you can't use derivative as a linear map, so the question wasn't even internally consistent.

    • CommentAuthorAnixx
    • CommentTimeJan 12th 2011 edited
     
    > not a real question" or "off-topic."

    Please tell me where do you see here "not a real question"?

    > then you have to specify which axioms of set theory you want to use

    OK. I would prefere to see in the answrer that this depends on the axioms chosen, not here.

    > Not to mention that if you want to allow non-differentiable functions you can't use derivative as a linear map, so the question wasn't even internally consistent.

    I was asking if there exist such operator on any functions that does not belong to the listed. I see no logic problems here. Do you? Is it required for a function to be differentiable for a non-derivative operator on it to exist? Do you have problems with elementary logic?
    • CommentAuthorMariano
    • CommentTimeJan 12th 2011
     

    Yes. That tone is surely going to help.

    • CommentAuthorAnixx
    • CommentTimeJan 12th 2011
     
    Sorry for the tone.

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